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Or you do a single chip solution using a PROM with 12 inputs and 10 outputs. Besides, your question is really underspecified and smells like an XY problem from miles away.
Where do the BCD digits come from that you need to convert? You’ll need 6 for converting 0 to Without knowing much more about the problem you are trying to solve, your best bet is to use a cheap microcontroller.
Of course you may use a PROM with 8 inputs and 8 outputs too. As you can imagine, this was a rather common function in electronics devices, hence why the chips are readily available.
Home Questions Tags Users Unanswered. The circuit with 6 ICs does convert all 3 digit BCD numbers to a correct result with 10 binary bits.
For a complete 3 digits BCD to binary converter you need 10 output bits for numbers from 0 to Jon 3, 7 If you go on eBay, you can get 20 year old Russian knockoffs for a couple of bucks apiece.
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The purpose of the many binary to BCD converter ICs that are around are to support 7-segment displays in the pre-cheap-microcontroller era.
SNN1 from Rochester Electronics
Without an MCU, it’s going to quickly be a mess of logic chips and wires, if you need more than two digits You’ll also need some extra protection logic, since with a 3-digit input there is always the chance that you will inadvertently try to enter a number in excess ofand the results of that will not be pretty.
You could also make something using discrete logic, which would be a good learning exercise, but will quickly become a reasonably complicated project in itself.
Xatasheet 3 5. Decimal to Binary [closed] Ask Question. The reason for this is that there is no common reason for a BCD to binary converter. See the How to Ask page for help clarifying this question.
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Dec 21 ’17 at Thumb wheels cheap from China? WhatRoughBeast 49k 2 28 Overall, in terms of circuit board size, power dissipation and error resistance, you’re much better off programming a 4k x 8 PROM such as a If this question can be reworded to fit the rules in the help centerplease edit the question. Then, of course, your 6 ICs will draw worst case as much as mA each, so you’re looking at mA. The extra protection logic is necessary only if the result should be represented with 8 bits 0 to only.
As has been pointed out in other answers, you can use the venerable and I do mean venerable Please clarify your specific problem or add additional details to highlight exactly what you need.
Yes, you’ll struggle to find one. Of course, those things have been obsolete for decades, so finding them is